Interaction of Discrete Charged Objects

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SUMMARY

The discussion focuses on solving a physics problem involving two charged objects, Q1 = +4Q and Q2 = -Q, positioned on the x-axis. The user has derived the equation 3d² - 8ds + 4s² = 0 to find the distance d from Q1 to a test charge +qo, which is located beyond Q2. The next step involves treating 's' as a known quantity to solve for d using the quadratic formula. The user seeks clarification on the approach and assistance in completing the solution.

PREREQUISITES
  • Understanding of Coulomb's Law and electrostatic forces
  • Familiarity with quadratic equations and their solutions
  • Knowledge of charge interactions and their effects on test charges
  • Basic algebraic manipulation skills
NEXT STEPS
  • Learn how to apply the quadratic formula to solve equations of the form ax² + bx + c = 0
  • Study the principles of electrostatics, particularly the behavior of charged objects
  • Explore graphical methods for visualizing forces between charged objects
  • Investigate the implications of varying charge magnitudes and distances on force calculations
USEFUL FOR

Students studying physics, particularly those focusing on electrostatics, as well as educators seeking to clarify concepts related to charged objects and force calculations.

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Homework Statement


Two charged objects Q1 = +4Q and Q2 = -Q are located on the x-axis. Q1 is at the origin and Q2 is at the x = +S m position. You also have a test charge +qo


Homework Equations


F = kQq/d2


The Attempt at a Solution



So you find that qo is past Q2 on the x-axis, and you set F1on3 = F2on3 and solve for d. I've done that and I'm left with the formula 3d2 - 8ds + 4s2 = 0. I don't know where to go from here, if I knew the value for S i could use the quadratic equation but I dont. Can anyone help me finish off this problem? Or tell me if I'm doing it wrong? Thanks
 
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Take "s" as a known quantity and solve for d in terms of "s".

ehild
 

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