Two charged objects are separated by a distance of L=0.4650 m as shown in the diagram.
Object Q1 has a charge of +5.250 nC. Object Q2 has a charge of +2.960 nC.
A) What is the magnitude and direction of the electric field at Point A, which is located a distance d=0.09300 m to the right of Object Q1?
B) If you were to place an electron at Point A, what would be the magnitude and direction of the force on the electron?
E= k (q/r^2)
F= (k*Q1*Q2)/ (r^2)
The Attempt at a Solution
A) [ (8.99E9) ((5.25E-9)/(.09300^2) ] - [ (8.99E9) ((2.96E-9)/(.372^2) ]=
= 5265 N/C = 5.265E3 N/C to the right THIS ANSWER IS CORRECT
B) The charge on an electron is -1.6E-19. I am also assuming that i will need Coulombs Law to solve.
[(8.99E9)(5.25E-9)(2.96E-9)] / (.4650) =.64610E-7 to the left
This is not the right answer and I'm not sure why. AM i even using the right formula?
Any help would be greatly appreciated. Thanks!
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