Interaction of radiation with matter

In summary, the problem statement is about calculating the momentum and energy of the products in a reaction involving 7Be4 and an electron. Relevant equations include p = mv, and the mass of 7Be and 7Li. The attempt at a solution involves using momentum and energy conservation, but the question does not provide information about the velocity of the daughter nucleus. However, it is not necessary as the neutrino is ultrarelativistic and should be treated like a photon. The energy-momentum relation for photons should be used instead.
  • #1
4
0
1. Problem statement

i am trying to calculate the momentum and energy of the products in the reaction

7Be4 + e -----> 7Li3 + neutrino

2. Relavant equations

p = mv
mass of 7Be = 7.016929 u
mass of 7Li = 7.016004 u


3. The attempt at a solution

i know that after the electron capture, the neutrino and the daughter nucleas will move in opposite directions with the same momentum magnitude, and so form momentum coservation

mv(Li) = mv(neutrino)

but how do i go about findig the 'v' of Lithium in order to calculate its momentum, mv. the question does not give any info on 'v'. ? Do i even need the value of 'v' or not. So that i can then put that 'v' into the equation of finding the energy of the daughter nucleas as:

1/2 * m(Li)*v^2(Li) = ( m(neutrino)/m(Li) ) * E(neutrino)

am i actually in the right path, i would greatly appreciate any directions?
 
Physics news on Phys.org
  • #2
Where do you use energy conservation? It is important here, together with momentum conservation.

the question does not give any info on 'v'.
It does not have to.

The neutrino is ultrarelativistic, you cannot use the nonrelativistic momentum. Treat it like photons instead. Do you know the energy-momentum relation for photons?
 
  • Like
Likes 1 person
  • #3
* The momentum of the neutrino is not going to be mv because it will be a relativistic particle.

* Did you apply energy conservation?
 
  • Like
Likes 1 person
  • #4
ohhh, Thank you, it's E^2 = (pc)^2 + (m0*c^2)^2

will apply it , hadn't considered the relativistic issue...
 

Suggested for: Interaction of radiation with matter

Replies
13
Views
547
Replies
8
Views
1K
Replies
2
Views
2K
Replies
6
Views
608
Replies
6
Views
1K
Replies
3
Views
383
Replies
16
Views
2K
Replies
12
Views
1K
Back
Top