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Given N= 1.2.3 + 2.3.4 + ... + n(n+1)(n+2), prove that 4N + 1 is a square (n is a positive integer)
The discussion centers on proving that for the arithmetic sequence defined by N = 1.2.3 + 2.3.4 + ... + n(n+1)(n+2), the expression 4N + 1 results in a perfect square for positive integers n. The formula for the sum of the sequence is established as (n+1)n(n-1)(n-2)/4. The key simplification involves demonstrating that (n+1)n(n-1)(n-2) + 1 is a square, which is a more manageable problem to solve.
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