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- Homework Statement
- Suppose we have a thin oil film (n=1.5) in air. The light strikes the film vertically. We use a spectrometer to see that an intensity maximum at wavelength of 600nm and a minimum at 300nm. And there is no minima inbetween. How thick is the film?

- Relevant Equations
- \delta=(2pi/lamda)

Phase difference is $\phi=\frac{2pi}{\lambda}* \Delta+\pi$

Phase difference, max: $\Delta \phi=2pim=\frac{2pi}{\lamda_{max}}*2nd$

Phase difference, max: $\Delta \phi=2pim=\frac{2pi}{\lamda_{min}}*2nd+pi$

Flim thickness: $d=100nm$

Set the equations equal to each other i got a d=-100nm which is strange. Can someone help?

Phase difference, max: $\Delta \phi=2pim=\frac{2pi}{\lamda_{max}}*2nd$

Phase difference, max: $\Delta \phi=2pim=\frac{2pi}{\lamda_{min}}*2nd+pi$

Flim thickness: $d=100nm$

Set the equations equal to each other i got a d=-100nm which is strange. Can someone help?