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Intergal current solution question

  1. Jun 6, 2009 #1
    here is the question and solution:

    http://i40.tinypic.com/2jd0xnd.gif

    its illegal to write an interval t and variable dt

    and i cant see how they get their expression.
    i got a different result
    [tex]
    dq=\int_{0}^{t}Idt'=It-0
    [/tex]

    even if i substitute in I the expression that i was given
    i still get a different result
    ??
     
    Last edited: Jun 6, 2009
  2. jcsd
  3. Jun 6, 2009 #2

    Cyosis

    User Avatar
    Homework Helper

    You assumed I was constant. The exercise, however, gives you an I that depends on t. You need to integrate that function. What result do you get when using that expression?
     
  4. Jun 6, 2009 #3
    worked thanks :)
     
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