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Homework Statement
see attachment
Homework Equations
log_{10}x=y
10^{y}=x
The Attempt at a Solution
Since I'm rather confused on reading a logarithmic scale, I thought I'd post this to see if I'm doing this right and/or if there's a better way to do the problem.
a) T=500 C
using the # of intervals we can say that if d=.01, x=.5 intervals so...
log(t)=.5
t=3.16 min
similarly for d=.1
log(t)=3.5 intervals
t=3162
change in time = 31623.16 = 3158.8min
b) same process but use x=.5 intervals and x=2.1
If this method does work, is there any way to interpolate values so I can be more exact? or is there a better way to do the problem in general?
thanks!
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