- #1

ehilge

- 163

- 0

## Homework Statement

see attachment

## Homework Equations

log

_{10}x=y

10

^{y}=x

## The Attempt at a Solution

Since I'm rather confused on reading a logarithmic scale, I thought I'd post this to see if I'm doing this right and/or if there's a better way to do the problem.

a) T=500 C

using the # of intervals we can say that if d=.01, x=.5 intervals so...

log(t)=.5

t=3.16 min

similarly for d=.1

log(t)=3.5 intervals

t=3162

change in time = 3162-3.16 = 3158.8min

b) same process but use x=-.5 intervals and x=2.1

If this method does work, is there any way to interpolate values so I can be more exact? or is there a better way to do the problem in general?

thanks!