What is the inverse of this logarithm equation?

[supernova1203]

Homework Statement

What is the inverse of this logarithm equation?

y=-log₅(-x)

i tried it and i got y=-5^(-x)hm.. you know how people say that if you want to find the inverse graph of something just switch the x and y coordinates from the table of values? Well i also tried that approach and apparently the inverse is y=log₅x

atleast that's how it looks on table of values and on the graph...i don't know why i went with the y=-5^(-x)I don't know if i got it right or not, someone kind enough to take a look and see if i got it right or not? or maybe just give me the solution outright so i know if i did it correctly or not? :P

 

[symbolipoint]

Your result is correct. If you start from your original equation, multiply both sides by negative 1, you can easily switch x and y, and carry couple simple steps to find y as a function of x.

 

[supernova1203]

hm... so y=log₅x is correct?

 

[symbolipoint]

hm... so y=log₅x is correct?

No! Your first result was correct. y=-5^(-x)

 

[supernova1203]

ahh ok ty

 

[symbolipoint]

Original equation: $y=-log_{5}(-x)$

$-y=log_{5}(-x)$
Now express exponential form :
$5^{-y}=-x$

Now, switch x and y to create inverse:
$5^{-x}=-y$,

and then simply, $y=-5^{-x}$

 

[Mentallic]

Homework Statement

What is the inverse of this logarithm equation?

y=-log₅(-x)




i tried it and i got y=-5^(-x)


hm.. you know how people say that if you want to find the inverse graph of something just switch the x and y coordinates from the table of values? Well i also tried that approach and apparently the inverse is y=log₅x

atleast that's how it looks on table of values and on the graph...i don't know why i went with the y=-5^(-x)


I don't know if i got it right or not, someone kind enough to take a look and see if i got it right or not? or maybe just give me the solution outright so i know if i did it correctly or not? :P

To check if you're right, when you get to the equation $x=-5^{-y}$, just plug that value of x into your original equation $y=-\log_5(-x)$ and see if you get an equality.