Interpretation of Bremsstrahlung diagram

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SUMMARY

The discussion centers on the interpretation of a Bremsstrahlung diagram, specifically regarding the emission of gamma rays by an electron. Participants clarify that the diagram includes an internal photon line, which does not represent an emitted gamma ray. The confusion arises from the visual representation, leading to questions about conservation laws and the roles of the photons depicted. Ultimately, it is established that only one gamma ray is emitted due to the electron's deceleration or acceleration near a nucleus.

PREREQUISITES
  • Understanding of Bremsstrahlung radiation
  • Familiarity with Feynman diagrams
  • Knowledge of conservation laws in particle physics
  • Basic concepts of photon emission
NEXT STEPS
  • Study the principles of Bremsstrahlung radiation in detail
  • Learn how to interpret Feynman diagrams effectively
  • Research conservation laws in quantum mechanics
  • Explore photon emission processes in particle interactions
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Students and educators in particle physics, physicists analyzing electromagnetic interactions, and anyone seeking to deepen their understanding of gamma ray emissions in relation to electron behavior.

rwooduk
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This is what we have been given in class:

nMbzaP0.jpg


I'm a little confused as the electron seems to emit two gamma rays? I understand that the process can't occur if there isn't interaction with a nucleus due to conservation of momentum. Please could someone confirm that the top gamma is the initial release due to deceleration / acceleration, and the lower gamma is there to satisfy conservation laws.

Thanks for any help.
 
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rwooduk said:
I'm a little confused as the electron seems to emit two gamma rays?

Why do you think the electron is emitting two gammas? One of the photons in the diagram is an internal line.
 
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Orodruin said:
Why do you think the electron is emitting two gammas? One of the photons in the diagram is an internal line.

Thanks. But internal in what sense?
 
Both ends are within the Feynman diagram, it does not leave/enter it => it does not get emitted.
 
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mfb said:
Both ends are within the Feynman diagram, it does not leave/enter it => it does not get emitted.

I didnt know that, many thanks!
 

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