vcsharp2003
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- Homework Statement
- What is the maximum number of points at which a circle and the graph of ##y =\sin{x}## can intersect?
- Relevant Equations
- ##y =\sin{x}##
##(x-a)^2 + (y-b)^2 = r^2##
The question is asking for the number of different solutions to the following two equations.
$$y=\sin{x}$$
$$(x-a)^2 + (y-b)^2 = r^2$$
Solving these is complex for me due to one of the equations being a trigonometric function. If I substitute y from the first equation into the second equation, I get the following.
$$(x-a)^2 + (\sin{x}-b)^2 = r^2$$
$$x^2-2ax+a^2 + \sin^{2}{x} -2b\sin{x} +b^2 = r^2$$
$$(x^2 + \sin^{2}{x})-2(ax+b\sin{x}) +(a^2 + b^2) = r^2$$
Normally an equation of degree 2 would have at most two different solutions, but even though the above equation is of degree 2 in ##x##, the introduction of ##\sin{x} ## probably means its not. I am stuck beyond this, so please help.
Can someone help me determine the number of different solutions?
$$y=\sin{x}$$
$$(x-a)^2 + (y-b)^2 = r^2$$
Solving these is complex for me due to one of the equations being a trigonometric function. If I substitute y from the first equation into the second equation, I get the following.
$$(x-a)^2 + (\sin{x}-b)^2 = r^2$$
$$x^2-2ax+a^2 + \sin^{2}{x} -2b\sin{x} +b^2 = r^2$$
$$(x^2 + \sin^{2}{x})-2(ax+b\sin{x}) +(a^2 + b^2) = r^2$$
Normally an equation of degree 2 would have at most two different solutions, but even though the above equation is of degree 2 in ##x##, the introduction of ##\sin{x} ## probably means its not. I am stuck beyond this, so please help.
Can someone help me determine the number of different solutions?
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