[Intro Dynamics] How to obtain v(t) from v(r) in 3D?

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SUMMARY

This discussion focuses on deriving the time-dependent velocity vector, ##\vec v(t)##, from a position-dependent velocity vector, ##\vec v(\vec r)##, in three-dimensional space. The participants explore the integral formulation for time, specifically $$\Delta t=\int_{r_{xi}}^{r_{xf}} \frac{d r_{x}}{v(r_x,r_y,r_z)}$$, and its applicability in 3D trajectories. The conversation emphasizes the necessity of understanding the relationship between position and velocity in multidimensional contexts, particularly through the formula $$t_{01}=\int_{l_0}^{l_1} \frac{dl}{v(l)}$$, which is crucial for analyzing particle motion.

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Leo Liu
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Homework Statement
Conceptual question
Relevant Equations
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We know that in 1D, we can perform the following steps to obtain velocity in terms of time if the velocity is a function of position:
$$v=f(x)$$
$$dt=\frac{dx}{v}$$
$$t_2-t_1=\int_{x_1}^{x_2}\frac{dx}{v}$$
$$x(t)\rightarrow v(t)$$

But I wonder if it is possible to obtain ##\vec v(t)## from ##\vec v(\vec r)##? Does it even make sense to do something like $$\Delta t=\int_{r_{xi}}^{r_{xf}} \frac{d r_{x}}{v(r_x,r_y,r_z)}$$?
 
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The formula for time
t_{01}=\int_{l_0}^{l_1} \frac{dl}{v(l)}
where l is 2d or 3d trajectory of the particle whose position and speed are defined as function of l , would be of your interest.
 

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