Intro physics proportion question

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The discussion centers on calculating the proportional size of a hydrogen atom when a proton is scaled up to the size of a marble. The user initially calculated the hydrogen atom's size to be 300 meters based on the scaling factor derived from the marble's radius. However, they seek clarification on how to properly set up the ratio to demonstrate that the hydrogen atom is consistently 50,000 times larger than the proton. The response emphasizes that the problem relies on proportional scaling using the known radii of both the proton and hydrogen atom. Understanding this ratio is key to accurately determining the enlarged size of the hydrogen atom.
dylanhouse
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Homework Statement



The radius of a proton is roughly 10^-15m, while the radius of a hydrogen atom is about 0.5x10^-10m. If we were to enlarge both proportionally until the proton was as large as a marble, about how large would the atom be?

Homework Equations





The Attempt at a Solution



I calculated an answer of 300m, but this doesn't seem correct for the size of a Hydrogen atom. I simply took the radius of a marble to be approximately 0.6cm, found the proton had to increase by 6x10^12 to become the size of the marble and multiplied this increase factor by the radius of the hydrogen atom and got 300 :$
 
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The proportion looks okay. The straightforward approach is to set up the ratios as an equation.

$$\frac{r_{hydrogen}}{r_{proton}} = \frac{r_x}{r_{marble}}$$
 
What is rx? I'd have (0.5x10^-10)/(10^-15)=rx/x? Assume the marble radius is x..
 
##r_x## is the unknown radius of the "inflated" atom.
 
I guess my question is how would I use that ratio to show that the atom is always 50,000 times larger than proton?
 
dylanhouse said:
I guess my question is how would I use that ratio to show that the atom is always 50,000 times larger than proton?

The ratio is a given. You have the radius of the proton, and the radius of the hydrogen atom. The rest is just proportional scaling (or comparison) of sizes.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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