Inverse Square Law: Calculating Intensity at Different Distances

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The discussion focuses on applying the inverse square law to calculate intensity at different distances from a point source. The first problem involves determining the intensity of infrared waves at 1 meter from a source, given its intensity at 2 kilometers. The second problem requires finding the light intensity from a candle when the distance is changed from 3 meters to 1 meter. Participants express confusion about manipulating the inverse square law equation, particularly with fractions. A suggestion is made to revisit basic fraction concepts to improve understanding and problem-solving skills.
emtis
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Homework Statement


Problem One: Two kilometres away from a point source of infrared waves, the intensity is 4 Mw−2. Calculate the intensity 1m away from the source.

Problem two: Light from a candle has an intensity of 20.0 units when a meter is placed 3.0m away. What is the reading on the light meter when it is brought to 1.0 m away?


Homework Equations


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The Attempt at a Solution


Yeah, about that. I'm not really sure where to start. I mean, I have the answers with me, and I think I am able to fill in the values for the inverse square law, but I don't know how to manipulate the equation with fractions to get the answer that I want. I always struggle here, because I ****ing hate fractions and I can't seem to get one thing write with them. I'd like to see the solution with respect to the given formula above please.
 
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Look at the first problem. You are given the intensity and distance for one measurement; let those be ##I_1## and ##d_1## respectively. You are also given another distance, and you want to find the intensity at that spot; let those be ##d_2## and ##I_2##. You have to solve the equation you have above for ##I_2##, and then plug in the numbers you have to get your answer.
 
If your problem is with fractions than I think you should go back to basics and solve many more fraction problems from some introductory text that includes lots of examples and exercises.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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