Invertible <=> F is 1-1 and onto

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SUMMARY

The discussion confirms that a function F is invertible if and only if it is both "1-1" (injective) and "onto" (surjective). This means that for every element b in set B, there exists at least one corresponding element a in set A such that f(a) = b, ensuring that F covers all elements in B. Additionally, the "1-1" property guarantees that no two elements in A map to the same element in B, allowing for the construction of an inverse function f^{-1}(b) = a.

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  • Knowledge of injective (1-1) and surjective (onto) properties
  • Familiarity with inverse functions
  • Basic set theory concepts
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jeff1evesque
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invertible <==> F is "1-1" and "onto"

Never mind, haha- found out

Does anyone know why the following is true:

F is invertible <==> F is "1-1" and "onto"?
 
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Yes it is true.

Say F maps from A to B then:

1) As F is onto every element in B corresponds to at least one element in A i.e. for all b \in B there is at least one a \in A such that f(a) = b.

2) As F is 1-1 every element in B can correspond to at most one element in A ie. f(a) = f(a&#039;) \Rightarrow a=a&#039;.

This is enough to be able to construct the inverse
f^{-1}(b) = a \mbox{ if and only if }f(a) = b
 

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