kraphysics said:
Sorry. I am having trouble following. Originally the question was why is the ionization energy of Helium the energy of its 1st energy level?
E 1= -2.18 * 10^18 J
General formula for energy is, En = -E1 / n^2
So to ionize it would be the change in E between final state and initial state, right? So that means that the electrons in the first orbital are brought out to infinity orbital?
Is what I'm saying correct?
Hydrogen, not helium (since hydrogen only has one electron).
Anyway, the way this works is that we define the zero energy level for the electron as the situation where it's infinitely far away from the nucleus, and stationary. In other words, no kinetic energy (relative the nucleus) and no potential energy (since it's infinitely far away from the nuclear attraction).
So in the orbitals (bound states) the energy of the electron is negative, because it's closer to the nucleus. So the ground state is the state where the electron has the lowest, most negative, energy. Lower than zero energy means the electron is bound - it has less energy than required to escape the attraction of the nucleus. But the electron can also have
more than zero energy. Because once the electron is free of the nuclear attraction it no longer has quanized energy levels, it can move freely. And so it can have
any energy then. So above zero you don't have orbitals or any discrete states, but a continuum of energy levels.
So the ionization energy isn't defined as the difference between the final and initial states, because the final state could have the electron flying away at any arbitrary speed. So instead it's defined as the
minimum energy required to remove the electron from the atom. Which means, the difference between zero, and the energy of the orbital the electron is in.
So since the ground-state energy of the one electron in hydrogen is -2.18 * 10^18 J, it has an ionization energy of that amount (without the minus sign). But you can still ionize the atom with any amount of energy that's greater than that.