Ionization percentage in the Saha equation

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SUMMARY

The discussion focuses on calculating the ionization percentage using the Saha equation, specifically the ratio n2/n1, which participants noted to be approximately 10^25. A participant confirmed their calculation of NII/NI as 139.9688 × 10^25 and expressed confusion regarding the conversion to percentage. The conversation emphasizes the importance of correctly interpreting the number density of free electrons (ne) in relation to the density of the star, suggesting the formula ne = (Density of star)/(2mp) for accurate calculations.

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tanaygupta2000
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Homework Statement
Find out the percentage of ionization in H2 gas at the centre of a star, given that the density of the star is 10^5 kg/m^3 and its temperature is 1.5 × 10^7 K.
(For H2, 2gi/ga = 1 & I = 13.6 eV).
Relevant Equations
n2/n1 = 1/n (2πmkT/h^2)^(3/2) 2g2/g1 exp(-I/kT)
Plugging-in the above data, I am getting n2/n1 to be of the order of 10^25 !
I know that the percentage is out of 100.
 
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Trying to clean up your post with LaTeX...

<br /> <br /> n2/n1 = 1/n (2πmkT/h^2)^(3/2) 2g2/g1 exp(-I/kT) <br />
 
Still working on it...
 
Okay, I'm not able to fix up your equation in the standard LaTeX that we use here at the PF. Please add a reply with your math properly formatted so we can try to help you. Tutorial on LaTeX is at the top of the page under INFO/Help. Thank you.
 
berkeman said:
Okay, I'm not able to fix up your equation in the standard LaTeX that we use here at the PF. Please add a reply with your math properly formatted so we can try to help you. Tutorial on LaTeX is at the top of the page under INFO/Help. Thank you.
unnamed.gif
 
Sir I am getting NII/NI = 139.9688 × 1025
I have checked my calculation.
How do I find the 'percentage'?
 
I think I am getting confused by ne (number density of free electrons) with the density of the star.
I think I need to use ne = (Density of star)/(2mp) and not directly 105.
 

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