Iron transforms from bcc to fcc.Ratio of nearest neighbour distance.

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SUMMARY

Iron undergoes a transformation from body-centered cubic (bcc) to face-centered cubic (fcc) structure at approximately 1180K. The task is to find the ratio of the nearest neighbor distance in fcc to that in bcc while assuming constant density. The correct formula for the nearest neighbor distance in fcc is a/√2, and for bcc, it is a(√3)/2. The calculated ratio of 0.8 is incorrect; the accurate ratio is 1.029, indicating a misunderstanding in the application of density and edge length in the transformation.

PREREQUISITES
  • Understanding of crystal structures: bcc and fcc
  • Knowledge of nearest neighbor distance calculations
  • Familiarity with density concepts in solid-state physics
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the relationship between density and edge length in fcc and bcc structures
  • Learn about phase transformations in metals, specifically iron
  • Explore the mathematical derivation of nearest neighbor distances in different crystal structures
  • Investigate the effects of temperature on crystal structure stability
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Students in materials science, metallurgists, and anyone studying phase transformations in metals, particularly those focusing on iron and its structural properties.

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Homework Statement


At about 1180K iron transforms into fcc structure from bcc structure which is also the structural form at room temperature.Assuming no change in density find the ratio of nearest neighbour distance in fcc structure to that in bcc structure.

Homework Equations


For fcc nearest neighbour distance is a/ 2(1/2)
For bcc " """"""" """" a(31/2) / 2[/B]

The Attempt at a Solution


I took the ratio of the above formula.I am getting 0.8 .But the given answer is 1.029.Clearly my method is wrong .Please help.[/B]
 
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sudipmaity said:

Homework Statement


At about 1180K iron transforms into fcc structure from bcc structure which is also the structural form at room temperature.Assuming no change in density find the ratio of nearest neighbour distance in fcc structure to that in bcc structure.

Homework Equations


For fcc nearest neighbour distance is a/ 2(1/2)
For bcc " """"""" """" a(31/2) / 2[/B]

The Attempt at a Solution


I took the ratio of the above formula.I am getting 0.8 .But the given answer is 1.029.Clearly my method is wrong .Please help.[/B]

This is possibly relevant: The problem statement doesn't say that the constant a (presumably, that's the length of one of the edges of the cube?) stays the same. It says that the density stays the same. So you need to compute the density as a function of a for fcc an bcc. Then you need to figure how a changes if the density stays constant.

That's just a guess as to what the problem might be.
 

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