Is 0.03 a Correct Focal Length Calculation for a 13 Field of View?

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questions_uk
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Hi. If using:

f (focal length) = a / ( 2 x arctan (theta / 2)) where a = 13 and is the Field of View

the value I get for the focal length is 0.03 and this seems too small. Unless the calculation has not been done right?

Thanks.
 
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Something is weird about your equation. If theta is an angle, it makes no sense to take the arctan of an angle.

questions_uk said:
the value I get for the focal length is 0.03 and this seems too small.

That depends. 0.03 mm would be too small. 0.03 m would actually be reasonable. 0.03 miles could be too large.

Moral: units are an important part of the answer.
 
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