Minimum Wire Length Calculation for Square Pattern in 10cm Square

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Homework Help Overview

The problem involves calculating the minimum length of wire needed for a specific pattern within a 10 cm square. The wire is arranged in a horizontal line across the middle of the square, with the ends connected to the nearest corners. The goal is to determine the minimum value of the horizontal segment's length, denoted as x.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the segment length x and the total wire length l, which includes additional segments to the corners. There is mention of using Pythagorean theorem to relate these lengths.
  • Some participants question the validity of the problem statement, particularly regarding the implications of setting x to 0 and whether the focus should be on minimizing the total length l instead.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the approach to solving for the minimum length, but there is no explicit consensus on the assumptions or the correct interpretation of the problem statement.

Contextual Notes

There are concerns about the clarity of the problem statement, particularly regarding the definition of the minimum value of x and its implications for the total length of wire. Participants are considering the constraints of the problem and how they affect the calculations.

squenshl
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Homework Statement


A wire pattern is inserted into a ##10##cm square by making a horizontal line in the middle of the square (not all the way across and with length ##x##) and connecting the ends of this line to the closest two corners. What is the minimum value of ##x##?

Homework Equations

The Attempt at a Solution


Let ##y## be the length of the wire from the end of ##x## to the corner of the square. This means the total length of the wire is ##l = x+4y##.

I extended the blue line ##x## to create a triangle then I used Pythagoras' to get ##y^2 = 25+\frac{(10-x)^2}{4}##.

Do I then throw this (meaning ##y##) into ##l## then differentiate with respect to ##x## then solve to get my minimum value for ##x## then ##y## which would give me the minimum length for ##l##.

Thanks!
 

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squenshl said:

Homework Statement


A wire pattern is inserted into a ##10##cm square by making a horizontal line in the middle of the square (not all the way across and with length ##x##) and connecting the ends of this line to the closest two corners. What is the minimum value of ##x##?

Homework Equations

The Attempt at a Solution


Let ##y## be the length of the wire from the end of ##x## to the corner of the square. This means the total length of the wire is ##l = x+4y##.

I extended the blue line ##x## to create a triangle then I used Pythagoras' to get ##y^2 = 25+\frac{(10-x)^2}{4}##.

Do I then throw this (meaning ##y##) into ##l## then differentiate with respect to ##x## then solve to get my minimum value for ##x## then ##y## which would give me the minimum length for ##l##.

Thanks!

If that is what you think you should do, why ask us? Just do it!

The point is that you need to start having confidence in your own methods, and you need to be willing to make a mistake, perhaps spending a lot of time on an erroneous approach, then throwing out the worksheets and starting again. That is how all of the homework helpers learned the subject!
 
The problem statements seems to be ill at least to me. The problem asks for the minimum value of ##x ##(which if understand correctly is the length of the segment in the middle of square). What prevents us from taking ##x=0##?
The only thing I can make is that you probably meant to say the value of ##x## that minimizes the total length ##l## cause that's what your method calculates.
 
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Delta2 said:
The problem statements seems to be ill at least to me. The problem asks for the minimum value of ##x ##(which if understand correctly is the length of the segment in the middle of square). What prevents us from taking ##x=0##?
The only thing I can make is that you probably meant to say the value of ##x## that minimizes the total length ##l## cause that's what your method calculates.
what he said (very small).jpg
 

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