I agree with Integral, though Integral certainly doesn't need my agreement in order to be correct ;)
However, I know that reading a proof umpteen times will not necessarily make it any clearer. Understanding the proof should be your goal, but if you don’t understand it yet...
leto said:
There is NEVER a point where you can stop the repetition and say that number = 1.
**The language really needs to be precise, and it isn't here, so we have to be especially careful and keep in mind that the conversation is informal and aimed at conceptual understanding.**
That said, the above quote is what I’ll try to get you to understand, because it doesn't seem like you actually understand it.
leto said:
I understand that the repetitions never stop, however, the amount of places from the decimal point also never stop.
You don’t need the “however”, in fact, you need to get rid of the “however”. On the right side of the decimal point, every decimal place has a 9 in it. The “amount of places from the decimal point” is the same as “the repetitions”. See?
leto said:
You are infinitely taking smaller and smaller steps closer to one. If infinity at some point arbitrarily fills the gap then why can't .999 repeating = 2, or any other number?
The gap is filled when infinity ends! :) And you already know that infinity doesn’t end. So the gap is never filled.
Another way of looking at it is that, if you are taking smaller and smaller steps, you never take a *last* step.
Note that, if the first step is .9, each successive step is 1/10 the size of the previous one, that is, multiply the size of the last step by 1/10 to get the size of the next step. 9/10, 9/100, 9/1000, 9/100000, ...
The size of each step is very important. Just getting smaller will not do, they have to get smaller by 1/10.
You cannot get to 2 because you never pass 1. You never pass 1 because the size of your steps is getting smaller by a very important amount, 1/10.
(Notice that you have already said "There is NEVER a point where you can stop the repetition and say that number = 1." You admit that .9 is less than 1. In order to get from .9 to 2, you must pass 1, since 1 is between .9 and 2. And so you must have assumed that the successive values 0.9, 0.99, 0.999, ..., "jump over" 1, or pass 1 without landing exactly on 1, or without being exactly equal to 1. Had you assumed that?)
You also never pass 1 because you never reach 1. This is the same as saying the gap is never filled or you never take a last step.
You can start at .9 then step to .99 then step to .999 and so on. Each step is closer to 1. And after each step, you only have to take a step “this size” to reach 1. But you can never take a step “this size” because you have to take a step 1/10 the size of your previous step, AND 1/10 the size of your previous step is always smaller than “this size”.
When you are at .9 you need to take a step of size .1 to reach 1.
But you can only take a step of size .09
See?
leto said:
There is NEVER a point where you can stop the repetition and say that number = 1.
I hope that cleared up any misunderstanding you had so far.
The next thing to understand is why 0.9999... = 1.000...
Perhaps taking another look at Integral’s proof or reading through other's posts will make this clear.
Happy thoughts
Rachel