Is a set with a 0 vector linearly independent?

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SUMMARY

A set containing the zero vector is always linearly dependent. In the discussion, matrices such as [1 0 3], [2 0 4], and [0 0 5] are confirmed to span a plane in R³, demonstrating linear dependence. The matrices [1 0 3 5], [3 0 2 4], and [2 0 1 4] also exhibit linear dependence, spanning all of R³. The presence of the zero vector in any set guarantees that the set cannot be linearly independent.

PREREQUISITES
  • Understanding of linear algebra concepts, specifically linear independence and dependence.
  • Familiarity with matrix representation and operations in R³.
  • Knowledge of vector spaces and their properties.
  • Ability to perform linear combinations of vectors.
NEXT STEPS
  • Study the properties of vector spaces in linear algebra.
  • Learn about the implications of the zero vector in linear combinations.
  • Explore examples of linearly independent and dependent sets in R³.
  • Investigate the concept of spanning sets and their significance in linear algebra.
USEFUL FOR

Students and professionals in mathematics, particularly those studying linear algebra, as well as educators teaching concepts of linear independence and dependence.

Sasor
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I don't know how to write out matrices nicely on this forum,

but suppose you have some matrices:[1 0 3]
[2 0 4]
[0 0 5]

This would, by definition, be linearly dependent, spanning a plane in r3..is this correct? Since c1=0, c2=anything, c3=0

where c1v1+c2v2+c3v3=0

With this:

[1 0 3 5]
[3 0 2 4]
[2 0 1 4]

Linearly dependent, spanning all of r3?

[1 4 0 5 2]
[2 3 0 2 4]
[2 9 0 1 1]

Linearly dependent, spanning all of r3?

Are these correct? does the 0 vector have any special properties with this?
 
Last edited:
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If a set contains the zero vector, then it is always linearly dependent.

I think you made a typo when writing the title.
 

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