Is acceleration magnitude constant for an object moving along an ellipse?

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Homework Help Overview

The discussion revolves around the motion of an object along an elliptical path, specifically focusing on the magnitude of the acceleration vector as a function of the parameters a, b, and ω. Participants are exploring whether the magnitude of the acceleration vector remains constant over time.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are examining the relationship between the position vector and the acceleration vector, with one participant attempting to derive the magnitude of the acceleration. Questions are raised regarding the interpretation of vector components and the method for calculating magnitudes.

Discussion Status

The discussion is active, with participants seeking clarification on vector definitions and calculations. Some guidance has been offered regarding the calculation of vector magnitudes, but there is no explicit consensus on the approach to determining the constancy of acceleration magnitude.

Contextual Notes

Participants are navigating potential assumptions about vector notation and the definitions of the variables involved. There is uncertainty regarding the correct method for calculating the magnitude of the acceleration vector.

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Homework Statement


An object is moving along an ellipse which is described by x(t)=acos([tex]\omega[/tex]t) and y(t)=bsin([tex]\omega[/tex]t). Determine magnitude of acceleration vector as a function of parameters a, b, and [tex]\omega[/tex]. Is magnitude of acceleration vector constant over time?

Homework Equations


r(t)=x(t)x+y(t)y
v=dx/dtx+dy/dty

The Attempt at a Solution


r(t)=acos([tex]\omega[/tex]t)x+bsin([tex]\omega[/tex]t)y
a(t)=dvx/dtx+dvy/dty
v=-a[tex]\omega[/tex]sin([tex]\omega[/tex]t)x+b[tex]\omega[/tex]cos([tex]\omega[/tex]t)y
a=-a[tex]\omega[/tex][tex]^{}2[/tex]cos([tex]\omega[/tex]t)x-b[tex]\omega[/tex][tex]^{}2[/tex]sin([tex]\omega[/tex]t)y=-[tex]\omega[/tex][tex]^{}2[/tex](acos([tex]\omega[/tex]t)x+bsin([tex]\omega[/tex]t)y
a=-[tex]\omega[/tex]2r(t)
 
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I assume that you mean the unit vectors along the axes x,y by "x" and "y" and both "r" and "a" are vectors. Your last equation is the relation between the vector of acceleration and the position vector. What is the magnitude of acceleration?

ehild
 
Am I approaching it incorrectly? Both "r" and "a" are vectors. I assume I have to find magnitude of vector "r" but am not certain how to do it.
 
Do you know how to calculate the magnitude of a vector from its components?

ehild
 
I believe I calculate it by doing the square root of its components squared. Is that right?
 

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