- #1

- 18

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However if I try to approach it as the expected value of Y=X^0.5 then I find fy(y) = 5*lny/y^4 and its expected value is 20/33.

What's wrong? Is it a right approach or are those two things different?

- Thread starter fateswarm
- Start date

- #1

- 18

- 0

However if I try to approach it as the expected value of Y=X^0.5 then I find fy(y) = 5*lny/y^4 and its expected value is 20/33.

What's wrong? Is it a right approach or are those two things different?

- #2

- 18

- 0

Ah, I got it, x is y^2.. not the other way around.

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