Is $\Bbb R$ homeomorphic to a cartesian product?

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    2017
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SUMMARY

The discussion centers on the mathematical proof that if the real numbers $\Bbb R$ are homeomorphic to a Cartesian product $A \times B$, then either set $A$ or set $B$ must be a singleton. This conclusion is derived from topological properties and the nature of homeomorphisms. The problem remains unsolved in the forum, indicating a need for further exploration and discussion among participants.

PREREQUISITES
  • Understanding of homeomorphisms in topology
  • Familiarity with Cartesian products in set theory
  • Basic knowledge of real number properties
  • Experience with mathematical proofs and logical reasoning
NEXT STEPS
  • Study the properties of homeomorphisms in topology
  • Explore examples of Cartesian products in set theory
  • Investigate singleton sets and their implications in topology
  • Review advanced topics in topology, such as compactness and connectedness
USEFUL FOR

Mathematicians, topology students, and anyone interested in advanced set theory and its implications in homeomorphic relationships.

Euge
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Here is this week's POTW:

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Prove that if $\Bbb R$ is homeomorphic to a cartesian product $A\times B$, then either $A$ or $B$ is a singleton.

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Remember to read the http://www.mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to http://www.mathhelpboards.com/forms.php?do=form&fid=2!
 
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No one answered this week's problem. You can read my solution below.
Let $(a,b)$ be a point of $A \times B$ corresponding $0$ under a homeomorphism $\Bbb R \to A \times B$. Then there is a homeomorphism $\Bbb R\setminus \{0\} \to (A\times B) \setminus \{(a,b)\}$. Therefore, $(A \times B)\setminus\{(a,b)\}$ is disconnected. Since $A \times B$ is connected, then $A$ and $B$ are connected. So if neither $A$ nor $B$ is a singleton, then $(A\times B)\setminus\{(a,b)\}$ is connected. ($\rightarrow\leftarrow$)
 

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