George Jones
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Mike2 said:Yes, of course. There is no argument there. Even if the Hubble constant were to decrease with time, the simple fact that space is expanding with time means that galaxies pick up speed with time which is an acceleration.
Not necessarily.
This much was know when the Hubble law was first discovered.
No, before the (1998) supernova data, it was widely believed that the universe was decelerating (near t = now). This is why people found the supernova data to be so surprising.
So am I now to believe that the supernova data just now discovered this effect? I don't think so. I'm sure they were pointing to an apparent increase in the Hubble constant when they say the word "acceleration".
No. I think people participating in this thread have tried repeatedly to tell you that this is not the case.
As an example of a decelerating (but still expanding) universe that has a Hubble constant that decreases with time, Consider a toy universe and galaxies A, B, C, D at three differents instants of cosmological time.
Table of proper distances D from Milky Way:
<br /> \begin{matrix}<br /> & | & A & B & C & D \\<br /> -- & | & - & - & - & - \\<br /> t = 1 & | & 1 & 2 & 3 & 4 \\<br /> t = 2 & | & 1.4 & 2.8 & 4.2 & 5.7 \\<br /> t = 3 & | & 1.7 & 3.5 & 5.2 & 6.9<br /> \end{matrix}<br />
Table of recessional speeds v from Milky way:
<br /> \begin{matrix}<br /> & | & A & B & C & D \\<br /> -- & | & - & - & - & - \\<br /> t = 1 & | & 0.5 & 1 & 1.5 & 2 \\<br /> t = 2 & | & 0.35 & 0.71 & 1.1 & 1.4 \\<br /> t = 3 & | & 0.29 & 0.58 & 0.87 & 1.2<br /> \end{matrix}<br />
The Hubble constant equals 1/2, 1/4, and 1/6 at times 1, 2, and 3.
Also, as can be seen, the universe is decelerating.
This toy model is a Freidman-Robertson-Walker universe that has its scale factor given by a(t) = t^{1/2}, and, qualitatively, echos the way we thought the universe behaved (near t = now) before we had the 1998 supernova data.
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