Is Centrifugal Force the Key to Understanding Rolling Coin Dynamics?

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SUMMARY

The discussion centers on the dynamics of a rolling coin, specifically examining the role of centrifugal force in understanding its motion. Key points include the relationship between the coin's velocity, gravitational potential energy, and rotational velocity. The minimum velocity for the coin to roll without slipping is identified as critical, while the existence of a maximum velocity remains debated. Participants clarify that centrifugal force in the coin's rotating frame balances gravitational force, impacting the coin's ability to maintain contact with the ground.

PREREQUISITES
  • Understanding of gravitational potential energy (GPE) and its formula, ##mg(R+r)##.
  • Knowledge of rotational dynamics and the relationship between rotational and translational velocity.
  • Familiarity with the concepts of centrifugal and centripetal forces.
  • Basic principles of motion in a rotating reference frame.
NEXT STEPS
  • Explore the mathematical derivation of minimum velocity for rolling without slipping.
  • Investigate the effects of varying mass distribution on a rolling object's dynamics.
  • Study the implications of centrifugal force in different inertial and non-inertial frames.
  • Examine real-world applications of rolling dynamics in mechanical systems.
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in the principles of motion and dynamics related to rolling objects.

pandafish
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Homework Statement
A coin of radius R and mass M has a point mass m fixed at a distance r from its
centre. Find the minimum and maximum velocities which the coin can roll along the
table.
Relevant Equations
Conservation of energy: the difference in kinetic energy when the point mass is at its highest point and when it is at its lowest is equal to the difference in gravitational potential energy.

$$\frac{1}{2}m_0v^2 - \frac{1}{2}m_1v^2 = 2mgr$$
I reasoned that at the coin's slowest velocity, the energy it has must just be enough for it to reach the highest potential configuration: when the point mass is directly above the centre of mass of the coin, and its GPE is ##mg(R+r)##. I used this to find the minimum velocity, but I can't think of a reason there would be a max velocity for the coin.
 
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pandafish said:
...
I reasoned that at the coin's slowest velocity, the energy it has must just be enough for it to reach the highest potential configuration
What happens to its rotational velocity while that happens?
 
The rotational velocity decreases until it is 0, where the point mass is at the highest point.
 
The rotational velocity decreases, but not necessarily must reach 0, where the point mass is at the highest point.
The statement shows us that the coin rolls along the table.

Once the mass passes its highest point, can you see the same force that slowed the coin down inducing the rotational velocity to increase?
 
Yes, gravitational force on the mass creates a torque that increases and decreases the rotational velocity as the coin rolls.
 
Excellent!
The mass gains and loses potential energy in a cyclic manner.
Then, what locations of the mass correspond to the minimum and maximum rotational velocity (or kinetic energy) of the coin as it rolls along the table?
 
When the mass is furthest from the table, the kinetic energy is lowest, and when the mass is closest to the table, the kinetic energy is greatest?
 
Exactly!
 
Oh, I think I understand now. Thank you
 
  • #10
1680452333843.png


Aren't they asking what is the minimum velocity ##v_c## that if the coin rolls without slipping it can continue to roll?

I can't see why there should be a maximum velocity though...🤔
 
Last edited:
  • #11
erobz said:
I can't see why there should be a maximum velocity though...🤔
At some velocity the coin will lift clear of the ground.
 
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  • #12
erobz said:
View attachment 324387

Aren't they asking what is the minimum velocity ##v_c## that if the coin rolls without slipping it can continue to roll?

I can't see why there should be a maximum velocity though...🤔
Yes, that is what I originally assumed the problem to be asking.

jbriggs444 said:
At some velocity the coin will lift clear of the ground.
Does this mean when the centripetal force on the point mass balances out its weight force, the coin would no longer be rolling?
 
  • #13
pandafish said:
Does this mean when the centripetal force on the point mass balances out its weight force, the coin would no longer be rolling?
Be careful. The coin as a whole has to lift clear of the ground.
 
  • #14
jbriggs444 said:
Be careful. The coin as a whole has to lift clear of the ground.
Just a clarification: Its a centrifugal force in the rotating frame of the coin that the point mass is feeling that balances the total weight, not a centripetal force , correct?
 
  • #15
erobz said:
Just a clarification: Its a centrifugal force in the rotating frame of the coin that the point mass is feeling that balances the total weight, not a centripetal force , correct?
One can use centrifugal force, centripetal force or centripetal acceleration in a description of the scenario. It depends on what frame of reference you choose to adopt and what balance equation you choose to write down.

But yes I agree that one possible balance would be centrifugal force versus gravitational force.
 

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