- #1
Bipolarity
- 776
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Consider the reaction:
[itex] ^{39}_{20}Ca \rightarrow ^{39}_{19}K + \beta^{+} [/itex]
I understand that a proton in the Calcium nucleus is being split into a neutron, which stays in the nucleus, and a positron, which gets ejected.
But if you look at the equation above, charge is not conserved. The only thing I can think of doing to balance is to consider the potassium product as a negative ion, but that makes no sense to me?
Or perhaps I am missing something. Or perhaps it has something to do with the number of electrons in play.
Any help is appreciated. Thanks!
BiP
[itex] ^{39}_{20}Ca \rightarrow ^{39}_{19}K + \beta^{+} [/itex]
I understand that a proton in the Calcium nucleus is being split into a neutron, which stays in the nucleus, and a positron, which gets ejected.
But if you look at the equation above, charge is not conserved. The only thing I can think of doing to balance is to consider the potassium product as a negative ion, but that makes no sense to me?
Or perhaps I am missing something. Or perhaps it has something to do with the number of electrons in play.
Any help is appreciated. Thanks!
BiP