Is Convolution and Integration: A True Equality in Mathematics?

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Discussion Overview

The discussion centers on the mathematical relationship between convolution and integration, specifically whether the equality \(\int f(x)g(x)dx = \int f(x)dx \ast \int g(x)dx\) holds true. Participants also explore whether similar relationships apply in summation.

Discussion Character

  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants question the validity of the equality \(\int f(x)g(x)dx = \int f(x)dx \ast \int g(x)dx\) and seek clarification on its truth.
  • One participant suggests differentiating both sides as a method to investigate the equality.
  • Another participant points out that \(\int f(x)dx\) and \(\int g(x)dx\) are real numbers, raising the question of how convolution applies to numbers.
  • There is a contention regarding whether the result of the convolution of two integrals is a function or a number.
  • One participant asserts that the result of the convolution is indeed a function, while another seeks to clarify the relationship between \(f(x)g(x)\) and \(f(x) * \int g(x) dx\).

Areas of Agreement / Disagreement

Participants express differing views on the validity of the proposed equality and the nature of convolution when applied to integrals and sums. The discussion remains unresolved, with no consensus reached on the main question.

Contextual Notes

There are assumptions regarding the nature of convolution and integration that are not fully explored, particularly in the context of real numbers versus functions. The mathematical steps involved in proving or disproving the equality are also not resolved.

Jhenrique
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I was verifying that:

02cdb0955d8b54c21acde435bcc14991.png


http://en.wikipedia.org/wiki/Convolution#Integration


But, I'd like to know if this equality is true:
\int f(x)g(x)dx \overset{?}{=} \int f(x)dx \ast \int g(x)dx

Subquestion: this theorem above can be applied in summation too?
\sum_{x}\left (f(x)\ast f(x) \right )\overset{?}{=}\left(\sum_{x} f(x)\right)\left (\sum_{x} g(x) \right )
\sum_{x}f(x)g(x) \overset{?}{=} \sum_{x}f(x) \ast \sum_{x}g(x)
Thanks!
 
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Jhenrique said:
But, I'd like to know if this equality is true:
\int f(x)g(x)dx \overset{?}{=} \int f(x)dx \ast \int g(x)dx

The easy way to check is differentiate both sides. What do you know about the derivative of the convolution.
 
Jhenrique said:
But, I'd like to know if this equality is true:
\int f(x)g(x)dx \overset{?}{=} \int f(x)dx \ast \int g(x)dx

But ##\int f(x) dx## and ##\int g(x)dx## are just real numbers, no? What is the convolution of two numbers?
 
pwsnafu said:
The easy way to check is differentiate both sides. What do you know about the derivative of the convolution.

That:
a63515c305a187bb7a3e71570429c3dc.png
 
R136a1 said:
But ##\int f(x) dx## and ##\int g(x)dx## are just real numbers, no? What is the convolution of two numbers?

No! The result is a function!

pwsnafu said:
The easy way to check is differentiate both sides. What do you know about the derivative of the convolution.

Results: f(x) g(x) = f(x) * ∫ g(x) dx

But, my ask remains! My as ask now is f(x) g(x) is equal to f(x) * ∫ g(x) dx ?
 
Last edited:

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