Is Convolution and Integration: A True Equality in Mathematics?

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The discussion centers on the mathematical equality involving convolution and integration, specifically questioning whether the equation \(\int f(x)g(x)dx = \int f(x)dx \ast \int g(x)dx\) holds true. Participants clarify that the integrals \(\int f(x)dx\) and \(\int g(x)dx\) yield real numbers, and thus their convolution does not produce a function. The consensus is that the equality does not hold, as the convolution of two numbers is not defined in the same way as the convolution of functions. The discussion also touches on the derivative of convolution as a method to verify these relationships.

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Jhenrique
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I was verifying that:

02cdb0955d8b54c21acde435bcc14991.png


http://en.wikipedia.org/wiki/Convolution#Integration


But, I'd like to know if this equality is true:
\int f(x)g(x)dx \overset{?}{=} \int f(x)dx \ast \int g(x)dx

Subquestion: this theorem above can be applied in summation too?
\sum_{x}\left (f(x)\ast f(x) \right )\overset{?}{=}\left(\sum_{x} f(x)\right)\left (\sum_{x} g(x) \right )
\sum_{x}f(x)g(x) \overset{?}{=} \sum_{x}f(x) \ast \sum_{x}g(x)
Thanks!
 
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Jhenrique said:
But, I'd like to know if this equality is true:
\int f(x)g(x)dx \overset{?}{=} \int f(x)dx \ast \int g(x)dx

The easy way to check is differentiate both sides. What do you know about the derivative of the convolution.
 
Jhenrique said:
But, I'd like to know if this equality is true:
\int f(x)g(x)dx \overset{?}{=} \int f(x)dx \ast \int g(x)dx

But ##\int f(x) dx## and ##\int g(x)dx## are just real numbers, no? What is the convolution of two numbers?
 
pwsnafu said:
The easy way to check is differentiate both sides. What do you know about the derivative of the convolution.

That:
a63515c305a187bb7a3e71570429c3dc.png
 
R136a1 said:
But ##\int f(x) dx## and ##\int g(x)dx## are just real numbers, no? What is the convolution of two numbers?

No! The result is a function!

pwsnafu said:
The easy way to check is differentiate both sides. What do you know about the derivative of the convolution.

Results: f(x) g(x) = f(x) * ∫ g(x) dx

But, my ask remains! My as ask now is f(x) g(x) is equal to f(x) * ∫ g(x) dx ?
 
Last edited:

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