Is Convolution and Integration: A True Equality in Mathematics?

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The discussion centers on the equality between the integral of the product of two functions and the convolution of their integrals. Participants question whether the equation ∫ f(x)g(x)dx equals ∫ f(x)dx * ∫ g(x)dx holds true, noting that the integrals yield real numbers, which complicates the convolution concept. The suggestion is made to differentiate both sides to verify the equality. Additionally, there is curiosity about whether similar principles apply to summation, with a focus on the relationship between sums and convolutions. The inquiry remains unresolved, emphasizing the need for clarity on the equality and its implications in both integration and summation contexts.
Jhenrique
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I was verifying that:

02cdb0955d8b54c21acde435bcc14991.png


http://en.wikipedia.org/wiki/Convolution#Integration


But, I'd like to know if this equality is true:
\int f(x)g(x)dx \overset{?}{=} \int f(x)dx \ast \int g(x)dx

Subquestion: this theorem above can be applied in summation too?
\sum_{x}\left (f(x)\ast f(x) \right )\overset{?}{=}\left(\sum_{x} f(x)\right)\left (\sum_{x} g(x) \right )
\sum_{x}f(x)g(x) \overset{?}{=} \sum_{x}f(x) \ast \sum_{x}g(x)
Thanks!
 
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Jhenrique said:
But, I'd like to know if this equality is true:
\int f(x)g(x)dx \overset{?}{=} \int f(x)dx \ast \int g(x)dx

The easy way to check is differentiate both sides. What do you know about the derivative of the convolution.
 
Jhenrique said:
But, I'd like to know if this equality is true:
\int f(x)g(x)dx \overset{?}{=} \int f(x)dx \ast \int g(x)dx

But ##\int f(x) dx## and ##\int g(x)dx## are just real numbers, no? What is the convolution of two numbers?
 
pwsnafu said:
The easy way to check is differentiate both sides. What do you know about the derivative of the convolution.

That:
a63515c305a187bb7a3e71570429c3dc.png
 
R136a1 said:
But ##\int f(x) dx## and ##\int g(x)dx## are just real numbers, no? What is the convolution of two numbers?

No! The result is a function!

pwsnafu said:
The easy way to check is differentiate both sides. What do you know about the derivative of the convolution.

Results: f(x) g(x) = f(x) * ∫ g(x) dx

But, my ask remains! My as ask now is f(x) g(x) is equal to f(x) * ∫ g(x) dx ?
 
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