Is e^2 Considered a Constant in Differentiation?

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SUMMARY

In the discussion regarding the differentiation of the function f(x) = x³ + e², it is established that e² is treated as a constant. The derivative of f(x) is calculated as f'(x) = 3x² + 0, confirming that the derivative of any constant, including e², is zero. While the chain rule can be applied, it is deemed unnecessary for this particular case. The consensus is clear: e² is indeed a constant in differentiation.

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Homework Statement



Derivative of f(x) = x3 + e2


Homework Equations



Dex = ex

D constant = 0

The Attempt at a Solution



f'(x) = 3x2 + 0?

Is e2 treated as a constant?
 
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Ryuk1990 said:

Homework Statement



Derivative of f(x) = x3 + e2


Homework Equations



Dex = ex

D constant = 0

The Attempt at a Solution



f'(x) = 3x2 + 0?

Is e2 treated as a constant?

Yes. Or you can use the chain rule. if u = f(x) = 2 and y = g(u) = e^u then

\frac {dy} {dx} = \frac {dy} {du} \frac {du} {dx}

since \frac {du} {dx} = 0 \frac {dy} {dx} = 0.
 
Ryuk1990 said:

Homework Statement



Derivative of f(x) = x3 + e2


Homework Equations



Dex = ex

D constant = 0

The Attempt at a Solution



f'(x) = 3x2 + 0?

Is e2 treated as a constant?
Not only is it treated as a constant, it is a constant. The derivative of any constant is zero. Period.

Using the chain rule certainly works, but it's definitely overkill, so not recommended.
 

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