Is E constant in simple Gaussian diagram?

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SUMMARY

The discussion centers on determining whether the electric field [E] is constant in a simple spherical Gaussian diagram. Participants highlight that the length of arrows emanating from the center can indicate variation; if arrows are of different lengths, [E] is not constant. Additionally, the spacing of arrows can also suggest variation, with tighter clusters indicating a change in field strength. The need for a standard convention for representing [E] in such diagrams is emphasized, although no specific convention was provided.

PREREQUISITES
  • Understanding of Gaussian surfaces in electromagnetism
  • Familiarity with electric field concepts
  • Knowledge of vector representation in physics
  • Basic skills in interpreting graphical representations of physical phenomena
NEXT STEPS
  • Research the conventions for representing electric fields in Gaussian diagrams
  • Study the relationship between electric field strength and distance from a charge
  • Learn about the implications of varying electric fields in electrostatics
  • Explore the mathematical formulation of Gauss's Law and its applications
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Students of physics, educators teaching electromagnetism, and professionals involved in electrical engineering or related fields will benefit from this discussion.

ZedCar
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Homework Statement



If you have a simple Gaussian diagram of spherical shape, and arrows pointing out from the centre indicating [E] how do you know if [E] is constant or if it varies?

Is it because the arrows are of slightly different lengths? (Though all eminating from the centre and going out past the circumference.) Does this indicate variation?

Or would variation be indicated by arrows in different areas being more tightly together than other areas?

Thank you.
 
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It depends upon what convention was used when the drawing was made.
 
Is there a standard convention for indicating whether [E] is constant or varies in a simple spherical Gaussian diagram?
 
Can you scan the diagram and post the image?
 
SammyS said:
Can you scan the diagram and post the image?

Unfortunately I don't have a scanner to hand.

But if I can describe it, it's simply...

A circle with arrows all pointing out from the same point at the circle centre, and all ending once outside the circle. They all seem evenly spaced apart from each other.

However, even though they all end once outside the circle, some of them are slightly longer than others.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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