Is e^-ln(x) equal to 1/x? | Homework Statement

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Homework Help Overview

The original poster is inquiring whether the expression e^-ln(x) is equivalent to 1/x, which involves concepts related to logarithms and exponentials.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the properties of exponents and logarithms, with one suggesting a verification method involving the relationship between -ln(x) and ln(1/x). Others prompt the original poster to reflect on their understanding of exponentiation.

Discussion Status

There is an ongoing exploration of the relationship between the expressions, with participants providing guidance on how to approach the verification of the original poster's question. Multiple interpretations of the expressions are being considered.

Contextual Notes

Participants emphasize the importance of showing effort before receiving assistance, indicating a focus on the learning process in the discussion.

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Homework Statement



is e^-ln(x) the same as 1/x ??

Homework Equations





The Attempt at a Solution

 
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What do you think?
 


What do you know about numbers and exponents to those numbers?

Let t be any real number. What can you do with e[tex]^{-t}[/tex] ?
 


Well perhaps a way of verifying your answer would be to note -ln(x) = ln(1/x); therefore, e^-ln(x) = e^ln(1/x). Another way is to note e^-ln(x) = 1/e^ln(x).
 


Recall:
PF rules said:
On helping with questions: Any and all assistance given to homework assignments or textbook style exercises should be given only after the questioner has shown some effort in solving the problem. If no attempt is made then the questioner should be asked to provide one before any assistance is given.
 

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