MHB Is f a Contraction Mapping on [1,∞)?

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The function f(x) = x^0.5 + x^-0.5 is being analyzed to determine if it is a contraction mapping on the interval [1, ∞). Attempts to apply the Mean Value Theorem (MVT) were unsuccessful, and conventional methods did not yield a reduction to the required form k|x-y|. For values 1 ≤ x < y < +∞, the difference |f(y) - f(x)| is expressed as (1/2√c)(1 - 1/c)|y - x|. A global maximum for the function F(c) = (1/2√c)(1 - 1/c) on [1, +∞) is found to be K = 1/3√3, which is less than 1, indicating that f is indeed a contraction mapping.
Poirot1
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f:[1,infinity)->[1,infinity)

$f(x)=x^{0.5}+x^{-0.5}$

I thought about using MVT but it doesn't work and I've tried showing it conventially but i can't reduce it to k|x-y|
 
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Poirot said:
f:[1,infinity)->[1,infinity) $f(x)=x^{0.5}+x^{-0.5}$ I thought about using MVT but it doesn't work and I've tried showing it conventially but i can't reduce it to k|x-y|

For $1\leq x <y<+\infty$ you'll get

$\left|f(y)-f(x)\right|=\dfrac{1}{2\sqrt{c}}\left(1-\dfrac{1}{c}\right)|y-x|$

Now, use that a global maximum for $F(c)=\dfrac{1}{2\sqrt{c}}\left(1-\dfrac{1}{c}\right)$ in $[1,+\infty)$ is $K=\dfrac{1}{3\sqrt{3}}<1$
 
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