# Is it specific capacitance (Csp) is proportional to current density?

1. Jan 2, 2013

### N.F. Zain

I've run the experiment. By varying the current and fix the mass of the electrode, I found out that the specific capacitance (Csp) is increased when applied current (I) is increased.

By using this formula,

Csp = 4I / [M*(dV/dt)],

where I is the applied current, M is the mass of both electrodes, and dV/dt is the discharging slope after the IR drop, respectively.

Current density = I/M,
where I is the applied current, M is the mass of both electrodes.

Logically speaking, we can see from the formula above that Csp is proportional to I, M is fixed for all samples, but most of the published journals have reported that Csp is decreased when current density (I/M) is increased.

How could this happen? Please somebody help me with the brief explanation. TQVM. :(

Here I attached the related journals to this problem,