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Homework Help: Is it specific capacitance (Csp) is proportional to current density?

  1. Jan 2, 2013 #1
    I've run the experiment. By varying the current and fix the mass of the electrode, I found out that the specific capacitance (Csp) is increased when applied current (I) is increased.

    By using this formula,

    Csp = 4I / [M*(dV/dt)],

    where I is the applied current, M is the mass of both electrodes, and dV/dt is the discharging slope after the IR drop, respectively.

    Current density = I/M,
    where I is the applied current, M is the mass of both electrodes.

    Logically speaking, we can see from the formula above that Csp is proportional to I, M is fixed for all samples, but most of the published journals have reported that Csp is decreased when current density (I/M) is increased.

    How could this happen? Please somebody help me with the brief explanation. TQVM. :(

    Here I attached the related journals to this problem,
    1) http://iopscience.iop.org/0957-4484...&spage=13574&stitle=Proc.+Natl+Acad.+Sci.+USA
  2. jcsd
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