Is Measureability Necessary for Proof of Pointwise Limit of Simple Functions?

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The discussion centers on the necessity of measurability for proving that every measurable function can be expressed as the pointwise limit of a sequence of simple functions. The original poster questions the critical role of measurability in this proof, suggesting that the statement could apply to all functions. However, it is established that without measurability, the sequence of functions may not retain the properties of simple functions, as demonstrated through the characterization of measurable functions and the properties of sigma-algebras. The proof relies on the fact that non-measurable functions do not guarantee the simple nature of the approximating functions.

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http://www.proofwiki.org/wiki/Measurable_Function_Pointwise_Limit_of_Simple_Functions
The following proof is shown in my book too. Basically it states that every measureable function can be written as the pointwise limit of a sequence of simple functions. Now, my problem is I don't see where the measureability of the limit-function is used crucially - so is the measureability really strictly necessary for the proof and if so where is it used? For me the statement might as well be all functions can be written as the pointwise limit of a sequence of simple functions?
 
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By Characterization of Measurable Functions and Sigma-Algebra Closed under Intersection, it follows that:
Ann2n={f≥n}
Ank={f≥k2−n}∩{f<(k+1)2−n}
are all Σ-measurable sets.
Hence, by definition, all fn are Σ-simple functions.

If f was not measurable, then you wouldn't know that the fns were actually simple functions
 
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