Is my calculation for work done correct?

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Homework Statement


Force magnitude at the beginning of the road s = 12 m is F1 = 10 N , at the end of the road F2 = 46 N. The force is acting in object's displacement direction. Calculate work done by uniformly changing force.

Homework Equations


A = Fs

The Attempt at a Solution


A = Fs = (F2-F1)s = 432 J

Is it correct?
 
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kaspis245 said:

Homework Statement


Force magnitude at the beginning of the road s = 12 m is F1 = 10 N , at the end of the road F2 = 46 N. The force is acting in object's displacement direction. Calculate work done by uniformly changing force.

Homework Equations


A = Fs

The Attempt at a Solution


A = Fs = (F2-F1)s = 432 J

Is it correct?
No.

You can write the force vs. displacement equation and do the calculus for the work done, or make a graph of the force-displacement and find the area under it, or , more easily since the force is uniformly changing with distance, try the average force approach when using your formula. Use all three methods if you want and compare results. Your approach is not correct.
 
What about now:

Handwritten graph of force F in N against displacement s in m, with a trapezoid ABCD under a rising line from B at F = 10 N to C at F = 46 N, ending at s = 12 m, and the area calculation A = (10 N + 46 N)/2 * 12 m = 336 J below.