Calculations for Hydraulic Jacks lifting a load

In summary, the smaller hand pump cylinder with an area of 2.0 cm2 is connected to a larger jack cylinder with an area of 10.0 cm2. The pressure acting on the piston in the jack cylinder is P2 and the force being applied is F2. The force being applied by the hand pump cylinder is F1 = 98.1 N. Using the formula P1 = F1/A1, we can determine that the pressure in the hand pump cylinder is also 4.905 N/cm^2. Since P1 = P2, we can calculate F2 using the formula F2 = P2*A2, which gives us a value of approximately 49.05 N. This is equivalent
  • #1
doconnor17dan
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Homework Statement
can somone check my working out ?
Relevant Equations
p=f/a
This cylinder is connected by a pipe to the larger diameter jack cylinder on the right where pressure p2 acts on the piston which has an area A2 and is able to lift a load equivalent to the force F2. The piston area of the hand pump cylinder is 2.0 cm2, the piston area of the jack piston is 10.0 cm2 and the force being applied F1 = 98.1 N

Here is my working out , would like to see If its correct ?

1. Which of the following is correct? 2. F1 > F2 3. F1 = F2 4. F1 < F2

2. Calculate the load being lifted by the jack cylinder in Kg's Pressure P1=P2 Force F1 = 98.1N P1=F1/A1 =98.1N / 2.0cm^2 = 4.905 N/cm^2 P2= P1 thus P2=4.905 N/cm^2 Thus P2=F2/A2 Thus F2 = P2XA2= 4.905x10 = 49.05N = approx. 49.05/0.102 = 5kg
 

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  • #2
Not to be more pedantic than usual but... the "Homework Statement" is where you put the exercise text, not the begging for help bit.

Ditto, to the other guy who did the same thing a minute ago.

And, right underneath the reply box is "LaTeX Guide", which - if used - can help people read what you've written.

And, your diagram's sideways.

And, something else, can't remember, oh yeah more bitching about the equations : lack of dimensions, lack of checking your work to see if it makes sense, etc.

Protip : the "Enter" key, on the right hand side of the keyboard, can be used to insert what's called a "line break".

As far as the answer is concerned, you can either do it in your head - not complex - or write it out nice and neat and people will check it for you and make rude comments when they have difficulty reading it.

Just sayin'. Carry on.
 
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  • #3
doconnor17dan said:
98.1N / 2.0cm^2 = 4.905 N/cm^2
?
 

FAQ: Calculations for Hydraulic Jacks lifting a load

1. How do you calculate the force required to lift a load using a hydraulic jack?

The force required to lift a load using a hydraulic jack can be calculated using Pascal's Principle, which states that pressure applied to a confined fluid is transmitted undiminished throughout the fluid. The formula is: Force = Pressure × Area. You need to know the pressure applied by the hydraulic fluid and the area of the piston to determine the force.

2. What is the relationship between the load and the hydraulic fluid pressure in a hydraulic jack?

The relationship between the load and the hydraulic fluid pressure is direct and proportional. According to Pascal's Law, the pressure applied to the fluid is transmitted equally in all directions. Therefore, if you increase the pressure, the force exerted by the jack increases proportionally, allowing it to lift heavier loads.

3. How do you determine the area of the piston in a hydraulic jack?

The area of the piston in a hydraulic jack can be determined using the formula for the area of a circle: Area = π × (radius)^2. Measure the diameter of the piston, divide it by 2 to get the radius, and then apply the formula to find the area.

4. What is the significance of the hydraulic fluid's pressure rating in a jack's performance?

The hydraulic fluid's pressure rating is crucial because it determines the maximum force the jack can exert. A higher pressure rating means the jack can lift heavier loads. It is important to ensure that the hydraulic fluid used is within the recommended pressure rating for the jack to avoid equipment failure or accidents.

5. How can you calculate the mechanical advantage of a hydraulic jack?

The mechanical advantage of a hydraulic jack can be calculated by dividing the output force by the input force. Alternatively, it can also be determined by comparing the area of the larger piston to the area of the smaller piston in the hydraulic system. The formula is: Mechanical Advantage = Area of Larger Piston / Area of Smaller Piston.

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