- #1

doconnor17dan

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- Homework Statement
- can somone check my working out ?

- Relevant Equations
- p=f/a

This cylinder is connected by a pipe to the larger diameter jack cylinder on the right where pressure p2 acts on the piston which has an area A2 and is able to lift a load equivalent to the force F2. The piston area of the hand pump cylinder is 2.0 cm2, the piston area of the jack piston is 10.0 cm2 and the force being applied F1 = 98.1 N

Here is my working out , would like to see If its correct ?

1. Which of the following is correct? 2. F1 > F2 3. F1 = F2 4. F1 < F2

2. Calculate the load being lifted by the jack cylinder in Kg's Pressure P1=P2 Force F1 = 98.1N P1=F1/A1 =98.1N / 2.0cm^2 = 4.905 N/cm^2 P2= P1 thus P2=4.905 N/cm^2 Thus P2=F2/A2 Thus F2 = P2XA2= 4.905x10 = 49.05N = approx. 49.05/0.102 = 5kg

Here is my working out , would like to see If its correct ?

1. Which of the following is correct? 2. F1 > F2 3. F1 = F2 4. F1 < F2

2. Calculate the load being lifted by the jack cylinder in Kg's Pressure P1=P2 Force F1 = 98.1N P1=F1/A1 =98.1N / 2.0cm^2 = 4.905 N/cm^2 P2= P1 thus P2=4.905 N/cm^2 Thus P2=F2/A2 Thus F2 = P2XA2= 4.905x10 = 49.05N = approx. 49.05/0.102 = 5kg