Is My Calculation of Resultant Force and Acceleration Correct?

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SUMMARY

The discussion centers on calculating the resultant force and acceleration for a box with a mass of 15 kg, pushed by a force of 9 N while experiencing a frictional force of 6 N. The resultant force is correctly calculated as 3 N (9 N - 6 N). Using the formula Force = Mass * Acceleration, the acceleration is derived as A = 3 N / 15 kg, resulting in 0.2 m/s². The participants confirm the calculations but note that the units must be consistent, emphasizing the importance of unit accuracy in physics problems.

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I'm I on the right track here?

Homework Statement


Determine the resultant force and acceleration for a box of mass 15kg being pushed with a force of 9N and a force of friction 6N acting to oppose.

Homework Equations



Force = Mass * Acceleration

The Attempt at a Solution



Force = 9N
Resultant Force = 9N - 6N = 3N (is this correct?)

Mass = 15Kg
Therefore,

3 = 15 * A
A = 3/15 m/s (this can't be right, can it?)
 
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01010011 said:
I'm I on the right track here?

Homework Statement


Determine the resultant force and acceleration for a box of mass 15kg being pushed with a force of 9N and a force of friction 6N acting to oppose.


Homework Equations



Force = Mass * Acceleration

The Attempt at a Solution



Force = 9N
Resultant Force = 9N - 6N = 3N (is this correct?)
yes
Mass = 15Kg
Therefore,

3 = 15 * A
A = 3/15 m/s (this can't be right, can it?)
Why not? But although your magnitude is correct, your units are off.
 

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