Is My Integration by Parts on \(\int \frac{1}{(x-1)(x+2)} \, dx\) Correct?

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SUMMARY

The forum discussion centers on the integration of the function \(\int \frac{1}{(x-1)(x+2)} \, dx\). The user attempted integration by letting \(u = x + 2\) and derived the result as \(\ln|x + 2| + C\). However, the correct approach involves using partial fraction decomposition to express the integrand as \(\frac{A}{x-1} + \frac{B}{x+2}\) before integrating. This method ensures accurate results for integrals of rational functions.

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Homework Statement



INTEGRAL 1/ (X-1)(X+2) DX

Homework Equations



I LET U = X+2 DU=X

The Attempt at a Solution

I GOT LN/(X+2)/+C I JUST DONT KNOW IF IM DOING IT RIGHT
 
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Use partial fractions or find the formula for that integral.

\int\frac{dx}{(x+a)(x-b)}
 

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