Is My Interpretation of the Integral Rule Correct?

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The discussion centers on the interpretation of integral rules, specifically focusing on the integration of functions involving derivatives. The user confirms their understanding of the integral rules, particularly the third rule, which states that ∫(cos(u) du) = sin(u) + C. They provide a specific example with u(x) = x², leading to the conclusion that ∫(cos(x²) * (2x) dx) indeed equals sin(x²) + C. The conversation clarifies that the integral of the derivative aligns with the fundamental theorem of calculus.

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christian0710
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Hi I'm tying to understand notations in Integration, and would really appreciate some help making sure that my understanding is right.My books writes

Let u and v be functions of x whose domains are an open interval I, and suppose du and dv exist for every x in I.Then it defines

1) ∫(du)= u + C
2) ∫(c*du) = c*∫(du)and
3) ∫(cos(u)du = sin u +CNow i do understand the first 2, but I want to make sure i understand the 3rd rule.

If u is a function of x with the equation u(x)=x^2

Then the derivative
du/dx= 2x

The differential
du=u'(x)dx

Now if it's true that du=u'(x)dx
Then it does make sense that ∫du =u+C because ∫du=∫u'(x)*dx and the integral of the derivative if u is u.

But if u=x^2

Then ∫(cos(x^2)*du = ∫(cos(x^2)*(2x)dx and this is = sin(x^2) + C as the statement above says.
because the derivative of sin(x^2) = cos(x^2)*(2x).

Is this the right interpretation?
 
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why is ∫(cos(x^2)*(2x)dx not equal to sin(x^2) + C? you said in the line below it that
christian0710 said:
derivative of sin(x^2) = cos(x^2)*(2x).
which is exactly what appears under the integral sign.
 
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cpsinkule said:
why is ∫(cos(x^2)*(2x)dx not equal to sin(x^2) + C? you said in the line below it that

which is exactly what appears under the integral sign.

Oh forgive me, that NOT was a BIG mistake ;)
You are right, it is e equal to it.
 

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