Is My Matrix Calculation Correct for Composite Reflections in Linear Algebra?

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SUMMARY

The standard matrix for the transformation T: ℝ² → ℝ², which first reflects points through the horizontal x1 axis and then through the line x2 = x1, is derived from the product of two matrices. The first matrix, A = [0 & 1; 1 & 0], represents reflection across the line y = x, while the second matrix, B = [1 & 0; 0 & -1], represents reflection across the x-axis. The resulting transformation can be expressed as the product AB, where the evaluation of ABv is performed as A(Bv).

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Students of linear algebra, educators teaching matrix transformations, and anyone interested in understanding composite reflections in two-dimensional space.

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Homework Statement



Find the standard matrix of T

T: \mathbb{R}^2 \to \mathbb{R}^2 first reflects points through the horizontal x1 axis and then reflects points through the line x2 = x1


The Attempt at a Solution



I almost always have to look at my book to remind myself what the standard matrix transformation for each transformation is

So I did

e1 becomes (which I will use \to) \to e1 (which doesn't change \to e2

That's column one. Also I am using David Lay's book, so I don't know words like "nullspace", "basis", etc...

e_2 \to -e_2 \to -(e_1)

Then I get

\begin{bmatrix}<br /> 0 &amp; -1\\ <br /> 1 &amp; 0<br /> \end{bmatrix}

Now my question is, am I right about the -(e_1)? I added brackets on purpose
 
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Yes, that's right. Note that this matrix, with both transformations, is the product of two matrices:
\begin{bmatrix}0 &amp; 1\\ 1 &amp; 0\end{bmatrix}\begin{bmatrix}1 &amp; 0\\ 0 &amp; -1\end{bmatrix}
Let's call these matrices A and B, where A reflects across the line y = x (i.e., it switches the x and y coordinates) and B reflects across the x-axis.

The transformation that reflects across the x-axis and then reflects across the line y = x, can be expressed as the product of A and B, in that order. The expression ABv is evaluated as A(Bv), where Bv reflects v across the x-axis, and then A reflects the vector Bv across the line y = x.
 

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