Is my simplified bullet drop equation accurate for long-range shooting?

[warfreak131]

Homework Statement

I was wondering if you guys could see if my equation on bullet drop is correct. I know there are more factors than what I am presenting, but this is only a simplified version...

The distance an object with 0 initial vertical velocity falls is $$d_{drop}=\frac{1}{2}gt^{2}$$, and $$t=t_{flight}$$, the total time the bullet is in flight.

The velocity of the bullet is $$v_{bullet}=\frac{d}{t}$$ and in this case, $$d=d_{target}$$, and $$t=t_{flight}=\frac{d_{target}}{v_{bullet}}$$.

Combine these two and you get: $$d_{drop}=\frac{gd_{target}^{2}}{2v_{bullet}^2}$$

Is this correct?

 

[Dadface]

Correct.

 

[warfreak131]

cool, so just a fun fact using this model, if you had to hit a target a mile away with a rifle that shoots at 2850 feet per second from the muzzle (assuming velocity stays constant along the path), you would have to shoot about 55 feet above the target