Is My Solution for the Antiderivative of 8x - 3 sec^2x Correct?

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The discussion centers on finding the antiderivative of the function f'(x) = 8x - 3 sec²x. The correct antiderivative is determined to be F(x) = 4x² - 3tan(x) + C, where C represents the constant of integration. The participant confirms the solution is accurate, utilizing the antiderivative formula for sec²x, which is tan(x).

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Antiderivatives - 8x - 3 sec^2x

Im not sure whether my answer to this antiderivative question is correct and would like your opinion.

1. The antiderivative statement asks: Find f

2. f prime (x) = 8x - 3 sec^2x
Most general antiderivative = F(x) + C
Antidefferentiation formula: Function = sec^2, Particular antiderivative = tan x

3. My attempt at a solution
= [(8x^2)/2] - 3tan x
= 4x^2 - 3tan x

Is this correct?
 
Last edited:
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looks good to me, nice job.
 
physicsman2 said:
looks good to me, nice job.

Ok, great, thanks.
 

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