Is My Solution for Magnetic Field and Force Correct?

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Homework Help Overview

The discussion revolves around a problem related to magnetic fields and forces, specifically involving the calculation of magnetic force, radius of curvature, time spent in motion, and distance traveled by charged particles in a magnetic field.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of magnetic force using the equation F=qvB and question whether the sine of an angle should be included in the calculation. There is also a consideration of the geometry of the situation, particularly regarding the direction of the velocity relative to the magnetic field.
  • Concerns are raised about the interpretation of the radius of curvature and the calculation of time spent, with one participant suggesting a reevaluation of the arc length used in the time calculation.
  • One participant points out potential inconsistencies in the problem statement regarding the direction of the magnetic field and the expected motion of electrons, suggesting that the problem may contain a "trick" element.

Discussion Status

The discussion is ongoing, with participants providing feedback on calculations and raising questions about the assumptions made in the problem. Some guidance has been offered regarding the interpretation of the magnetic force and the geometry involved, but there is no explicit consensus on the correctness of the original poster's solution.

Contextual Notes

Participants note potential issues with the problem statement, including the direction of the magnetic field and its implications for the motion of charged particles, which may require clarification from the instructor.

bckcookie
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Homework Statement



As attached file! Please advise me my solution is right or not! Thanks a lot!

Homework Equations



F=qvB - (1)
R=mv/eB
d/t = v
length of arc = 2pi(R)
sinθ=a/c

The Attempt at a Solution



a) the magnetic force,
F = qvb
=1.6x10^-19 x 10^7 x 0.03N
= 4.8x10^-14N
(does it need to product with sin 45degree?? please advise!)

b) the radius of curvature
R = mv/eB
= (9.11 x 10^-31kg x 10^7) / 1.6x10^-19 x 0.03
=1.90 x 10^-3m

c) The time spend
=The length of arc / v
= 2∏R / v
= 1.194 x 10^-9s

d) the distance of x
= 2Rsin45
= 2.687 x 10^-3 m
 

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bckcookie said:

Homework Statement



As attached file! Please advise me my solution is right or not! Thanks a lot!

Homework Equations



F=qvB - (1)
R=mv/eB
d/t = v
length of arc = 2pi(R)
sinθ=a/c

The Attempt at a Solution



a) the magnetic force,
F = qvb
=1.6x10^-19 x 10^7 x 0.03N
= 4.8x10^-14N
'Looks right! :approve:
(does it need to product with sin 45degree?? please advise!)
Think about what the cross product means. The magnitude of [itex]\vec A \times \vec B[/itex] is the full [itex]AB[/itex] only if [itex]\vec A[/itex] and [itex]\vec B[/itex] are perpendicular. Is the velocity perpendicular to the magnetic field? (Hint: you need to think in three dimensions. :wink:)
b) the radius of curvature
R = mv/eB
= (9.11 x 10^-31kg x 10^7) / 1.6x10^-19 x 0.03
=1.90 x 10^-3m
'Looks right. :approve:
c) The time spend
=The length of arc / v
= 2∏R / v
= 1.194 x 10^-9s
Try that one again. 2πR is the circumference of an entire circle of radius R, not just an arc length.
d) the distance of x
= 2Rsin45
= 2.687 x 10^-3 m
'Looks right to me. :approve:
 
By the way, I just noticed that something is not quite right with the problem statement. Either that, or it's a "trick" question. You might want to tell you instructor about this.

According to attached figure, the magnetic flux density is going into the page (denoted by the 'x's). That, combined with the direction and orientation of the arrows, and the fact that electrons are negatively charged, the electrons would not curl around in a counter-clockwise direction as the problem indicates. Instead, they would curl around in a clockwise direction, and exit the magnetic field at some distance x *below* where they entered -- not above.

Either the figure needs to be redrawn to show the magnetic field coming out of the page, OR the magnetic flux density should be changed from 0.03 T to -0.03 T, OR the direction of the arrows need be to be reversed, OR the electrons should be replaced with positrons.

Keeping everything as it is, x will end up being negative, thus you'll have to redo parts c) and d).
 
you are right! Thanks for your hints!
 

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