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If [tex]\tilde{p}[/tex] is a one-form, then does [tex]\tilde{p}(\vec{a} - 3\vec{b}) = \tilde{p}(\vec{a}) - 3\tilde{p}(\vec{b})[/tex]?
The discussion confirms that one-form multiplication is indeed commutative. Specifically, if \(\tilde{p}\) is a one-form, then the equation \(\tilde{p}(\vec{a} - 3\vec{b}) = \tilde{p}(\vec{a}) - 3\tilde{p}(\vec{b})\) holds true. This property is essential for understanding linear transformations in the context of differential geometry. The conclusion is that one-forms maintain linearity under scalar multiplication and addition.
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