Is R^n Euclidean Space a vector space too?

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Euclidean space R^n is indeed an example of a vector space, as it satisfies the properties required for vector spaces. While matrices of dimensions 1x2 or 2x1 can represent vectors in R^2, they are not vectors in R^n in a general sense. The discussion highlights that R^n is geometric, with defined points and distances, but lacks the algebraic operations necessary for a vector space unless these operations are explicitly defined. When operations such as addition and scalar multiplication are defined, R^n can be viewed as a natural correspondence to an n-dimensional vector space. Therefore, R^n can function as a vector space under the appropriate definitions of operations.
bacte2013
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Dear Physics Forum personnel,

I am curious if the euclidean space R^n is an example of vector space. Also can matrices with 1x2 or 2x1 dimension be a vector for the R^n?

PK
 
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bacte2013 said:
I am curious if the euclidean space R^n is an example of vector space.

Yes.

Also can matrices with 1x2 or 2x1 dimension be a vector for the R^n?

No clue what you mean.
 
micromass said:
Yes.
No clue what you mean.
As for the second question, I mean if the 1x2 matrix (a1, a2) or its 2x1 form (column vector) can be considered as a vector for the R^2 since the R^2 is basically the collection of real numbers in the ordered pair (a, b)?
 
There is a linear isomorphism between the ##1\times 2##-matrices and ##\mathbb{R}^2##, yes.
 
The Eulclidean space Rn is geometric- there are such things as points and distances defined but no "operations". A vector space is algebraic we must have operations such as sum and scalar multiplication defined. Of course, for, finite dimensional Rn, we can define the sum as (x1, x2,... , xn)+ (y1, y2, ..., yn)= (x1+ y1, x2+ y2... , xn+ yn) and scalar multiplication defined as a(x1, x2, ..., xn)= (ax1, ax2, ..., axn). If we consider those operations as "natural" then we can think of this as a "natural" correspondence between Rn and an n dimensional vector space.[/sub][/sub]
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

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