AndreiB said:
LIGO makes measurements at 10 KHz
LIGO is not the tool we use to measure the mass distribution of the Earth. It is not suitable for that purpose. Measuring gravitational waves is not the same thing.
AndreiB said:
Practically, yes, but in theory this doesn't need to be the case.
You can't just wave your hands and say what should be true "in theory". You have to actually show that the theory supports your claim.
AndreiB said:
A small wobble shouldn't take more time to measure than a large one.
Measuring the mass distribution of the Earth is not the same as measuring a single wobble.
AndreiB said:
I don't think there is any theoretical limitation of that time.
See my response about theory above.
AndreiB said:
If you send a stream of photons to the slits in a 2-slit experiment and, by detecting those photons you could, in principle, detect which slit the particle passed, no interference would be observed regardless of the fact that you actually detect those photons or not.
You are misdescribing this. If you don't actually detect the photons, you don't know whether or not there is interference: to know whether or not there is interference, you
have to detect the photons.
What you
don't have to "detect" (in the sense of "a human observes") is the output of the which-way detector: just the fact that the which-way detector is present is enough. So it's the
presence of the which-way detector--the fact that there is an extra interaction in the path of the photons--that removes the interference.
In the case you're talking about,
if there is a "mass distribution detector" present (and if it is actually capable of distinguishing mass distributions on the appropriate time scale), then you are correct that no human has to actually read its output for the "live cat" and "dead cat" alternatives to decohere (i.e., not interfere with each other). However, the detector still has to
be there. If it is
not there, then the fact that it
could have been there is irrelevant. Just as, if a which-way detector is
not there in a double slit experiment, there is interference, even though there wouldn't have been if the detector
were there. And I was saying that, since it is perfectly possible to run the experiment with such a detector
not there, you cannot make fully general claims based on what would have happened if it
were there.