Is Space-Time Curvature Zero Inside a Spherical Cavity at Earth's Center?

  • Context: Graduate 
  • Thread starter Thread starter lightarrow
  • Start date Start date
  • Tags Tags
    Cavity Curvature
Click For Summary

Discussion Overview

The discussion centers on the nature of space-time curvature inside a spherical cavity located at the center of the Earth, exploring whether the curvature is zero or non-zero according to General Relativity (GR) compared to Newtonian gravity. The scope includes theoretical considerations and interpretations of gravitational fields and curvature tensors.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants assert that the Newtonian gravitational field at the center of the Earth is zero, suggesting that GR may yield the same result.
  • Others argue that while the Newtonian gravitational field is zero, the curvature tensors (G_{ab} and R_{abcd}) are non-zero at the center of the Earth due to the non-zero stress-energy tensor (T_{ab}).
  • A participant highlights the ambiguity in the term "gravitational field," suggesting that different interpretations may lead to varying conclusions about curvature and gravity.
  • One participant questions the relationship between tidal forces and curvature, noting that tidal forces should be zero inside a cavity with a uniform field.
  • Another participant proposes a Newtonian approach to analyze tidal forces, indicating that the net force is due to the mass enclosed within a certain radius, leading to a force proportional to distance from the center.
  • Additional insights are provided regarding the modeling of massive objects in GR, including the behavior of perfect fluids and the implications for static spherically symmetric bodies.
  • Some participants mention the challenges of generalizing these concepts to more complex shapes, such as oblate spheroids, and the limitations of existing models.

Areas of Agreement / Disagreement

Participants express differing views on the nature of curvature inside the cavity, with some asserting it is zero while others maintain it is non-zero. The discussion remains unresolved, with multiple competing interpretations of gravitational fields and curvature.

Contextual Notes

There are limitations regarding the assumptions made about gravitational fields and curvature, as well as the dependence on definitions of terms like "gravitational field." The discussion also touches on the complexities of modeling gravitational effects in varying contexts.

  • #31
You need to be more precise

mendocino said:
Let's forget about gravitational field for a moment and talk about measured quantity? For example, will the clock runs slowly at the center and will someone experienced a force inside the cavity?

Hi, mendocino, this question actually is a very good illustration of why I keep insisting that saying "the clock runs slow" somewhere or even that "time slows" somewhere is Not A Good Idea. Rather, the world lines of radially outgoing time signals are modeled by radial null geodesics and these tend to spread apart in a Schwarzschild vacuum. IOW, an ideal clock can only run slow compared to another ideal clock, and the way in which this comparison is carried out is crucially important.

To keep things manageable, we typically seek a simple operationally significant way of effecting the comparison; one of the simplest is to assume that both clocks A,B lie on the same radius and to look at radial null geodesics from A to B and vice versa. In this case, we have the added complication that the homogeneous isotropic material of which our spherical object with concentric cavity is made, is presumably not transparent to light, and light (or radio waves) presumably travels more slowly inside this material than in vacuo.

Be this as it may, you more or less said what A you have in mind (unless you don't mean, as I guess, the static observer at the very center of the cavity), but not what B, so you need to clarify that before we can compute the answer you seek. You also need to clarify whether you are willing to accept a weak-field approximation or not. And if the answer is "not", you should wait until I get around to generalizing the Newtonian theory in "What is the Theory of Elasticity?" Or else look up previous posts by myself from many years ago in sci.physics.relativity in which I worked this out for the case of a simple model of a perfect fluid ball (no cavity), the Schwarzschild fluid.

However, it should be clear just from looking at the Newtonian potential (see my plot in "What is the Theory of Elasticity?") that this scenario involves the behavior of geodesics "in the large". That is, we should expect a "time dilation" effect (the magnitude depends upon the details you haven't specified), even though the cavity is locally isomorphic to Minkowski spacetime, i.e. locally flat.

(Re what pervect said, this is a completely different concept from the concept of "locally geodesic" or sometimes "locally flat" charts, among which Riemann normal charts are particularly important. The terminology in this subject can sometimes be confusing, and is sometimes incompletely standardarized! If you stay alert to the possibility of confusion, you can probably avoid trouble. In particular, note that "locally flat spacetime" uses "local" in the standard sense of manifold theory, meaning "local neighborhood", whereas "locally flat charts" are defined at the level of the metric tensor and its derivatives at a single event. The latter usage is deprecated because it conflicts with the mathematical terminology required for much modern "geometric" physics, e.g. for fiber bundles. For more about normal charts, see Poisson, A Relativist's Toolkit.)

As for "force", if you were asking whether a stationary observer at the very center of the cavity in a Newtonian model experiences a force, the answer is self-evident from symmetry. (In what direction would the force vector point?) In gtr, there is no notion of "gravitational force", but you can ask whether the stationary observer at the center of the cavity is an inertial observer or not. If not, he must use a rocket engine (or taut cables) to maintain his position, and thus must feel a nongravitational force, corresponding geometrically to the path curvature of his world line. (In what direction would the force vector point?)
 
Last edited:

Similar threads

  • · Replies 32 ·
2
Replies
32
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 14 ·
Replies
14
Views
5K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 16 ·
Replies
16
Views
1K
  • · Replies 35 ·
2
Replies
35
Views
5K