Is T(x,y) = (x,0) a linear transformation

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SUMMARY

The transformation T(x,y) = (x,0) is confirmed as a linear transformation based on the properties of vector addition and scalar multiplication. The discussion demonstrates that T(v+w) equals T(v) + T(w) and T(cv) equals cT(v), fulfilling the criteria for linearity. It is essential to specify that x and y are real numbers for T to be a function from R² to R². Additional considerations include verifying T(0) = 0 and T(-v) = -T(v) to reinforce the linear transformation properties.

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  • Basic knowledge of functions from R² to R²
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Homework Statement



I have to determine whether the following is a linear transformation

T(x,y)=(x,0)

Homework Equations





The Attempt at a Solution



again, let v=(v1, v2) and w=(w1,w2)

then, T(v+w)=T(v1+w1, v2+w2)=(v1+w1, 0)

and, T(v)+T(w)=(v1+w1, 0)
so the first condition holds.

AND:

let c be a constant:
T(cv)=T(cv1,cv2)=(cv1, 0)=c(v1,0)=cT(v)
so both conditions hold
therefore it's linear transformation
is that correct?
 
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You haven't said what x and y are! If they are real numbers, that is that T is a function from R2 to R2, then yes, those are exactly what you need to show. (Of course, taking c= 0 in the second shows T(0)= 0 and taking c= -1 shows T(-v)= -T(v) which are required by not necessary to prove separately.)
 
yea it isedit: nevermind listen to halls, you do need to be more precise with this kind of thing probably
 

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