Is tangential force the same as centripetal force?

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SUMMARY

The discussion centers on the calculation of tangential blade loading for rotor blades attached to a disc rotating at 15,574 RPM with a radius of 220 mm. A force of 8 kN/rad acts on the blades, alongside a tangential force of 600 N/rad. Participants clarify that centripetal force acts perpendicular to the velocity of the rotor, while tangential force acts in the direction of motion. The confusion regarding the term "tangential blade loading" and the meaning of ".../rad" is addressed, emphasizing the need for a clear definition to proceed with calculations.

PREREQUISITES
  • Understanding of angular velocity and its calculation.
  • Familiarity with the concepts of centripetal and tangential forces.
  • Knowledge of centrifugal acceleration and its formula: f = mv²/r.
  • Basic principles of rotor dynamics and blade loading concepts.
NEXT STEPS
  • Research the definition and calculation methods for "tangential blade loading."
  • Learn about the relationship between angular velocity and tangential force in rotating systems.
  • Study the implications of forces acting on rotor blades in rotorcraft dynamics.
  • Explore the significance of the ".../rad" notation in force calculations related to rotational motion.
USEFUL FOR

Mechanical engineers, aerospace engineers, and students studying rotor dynamics or fluid mechanics will benefit from this discussion, particularly those involved in the design and analysis of rotor systems.

michelle90
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Homework Statement



Rotor blades attatched to a disc rotate.
The rotor blades rotate at a speed of 15574rpm. The blades are 220mm from the centre of the disc.

These blades are attatched to a disc that is 400mm in diameter.
A force of 8kN/rad acts upon the blades and 600N/rad. (see picture)


Calculate the tangential blade loading.

Not too sure if centripetal force is the same as tangential force though?

Homework Equations



(itex)f=mv^2/r(/itex)

The Attempt at a Solution




First calculated the centrifugal acceleration

(itex)=Mω^2r(/itex)
Centrifugal acceleration = 53197m/s

Then find the centrifugal force

(itex)f=mv^2/r(/itex)

I have the velocity and can obtain the mass and radius.

I'm not so sure this is the right way to solve the tangential blade loading??
I need to find angular acceleration?

Thanks for the in advance help guys.
 

Attachments

  • Disc loads.PNG
    Disc loads.PNG
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A centripetal force is a force perpendicular to the instantaneous velocity of a point on the rotors. A tangental force is a force in the directioni (or exactly opposite of the direction) of a point on the rotors.

michelle90 said:
A force of 8kN/rad acts upon the blades and 600N/rad.
What does the ".../rad" mean in this problem statement?
 
It means per radian.

So to calculate the tangential force I would need to angular velocity and then use the formula:

Pr=I_oa
 
rcgldr said:
What does the ".../rad" mean in this problem statement?

michelle90 said:
It means per radian.
So the force is a function of radians and is increasing as the rotors rotate, so at 0 radians, the force is 0, at 1 radian, the force is 8kN, at 2 radians, the force is 16kN, ... . Are you sure this is what the problem intended?
 
rcgldr said:
So the force is a function of radians and is increasing as the rotors rotate, so at 0 radians, the force is 0, at 1 radian, the force is 8kN, at 2 radians, the force is 16kN, ... . Are you sure this is what the problem intended?

The problem is to find the force acting on the circumference of the disc.
There are blades that attach to this disc which make up a rotor blade.
The forces shown (in the .jpg ) are those acting upon the blades.
 
rcgldr said:
What does the ".../rad" mean in this problem statement?

michelle90 said:
It means per radian.

michelle90 said:
The problem is to find the force acting on the circumference of the disc. There are blades that attach to this disc which make up a rotor blade.
The forces shown (in the .jpg ) are those acting upon the blades.
The ".../rad" doesn't make sense. I think that the problem statement and the diagram should not have that ".../rad" component, in which case, at 220mm from the center of the disc, you have 8kN of centripetal force and 600N of tangential force. I'm not sure what the term "tangential blade loading" means. I did a web search for "blade loading" and I see math involving "tangential mean swirl velocity".
 
rcgldr said:
The ".../rad" doesn't make sense.
I believe it is treating the blades - presumably narrow and numerous - as a continuum. In a sector of angular width δθ, the centripetal load is 8000 δθ N.
I don't understand the diagram. What part of the blade attaches to the disc, and how? It sounds like the outer end of the blade extends 20mm beyond the disc, but in that case I'm not sure why the disc diameter matters.
To have any hope of answering this question, you need a clear definition of what is meant by "tangential blade loading". How is it different from the 600N/rad given? Or maybe that multiplied by 2pi? I can't find one.
 

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