- #1
- 42
- 0
Is the 4-velocity always a space-tipe 4-vector?
Just calculate its square in the reference frame where the ordinary velocity is equal to zero.Ok, so if I have a given 4-velocity how can I show in terms of mathematics that it is time-like ?
WHY a 4-velocity that travel slower than light satisfies t² - x² - y² - z² = 1 ?!!
Wow. Might you be able to find a textbook that was written after 1936? Because that was about the last time anyone ever used the ict convention. In that convention, the norm of the 4-velocity will always be -1, and is still timelike, because that is what timelike means in that convention. Get a newer book. Seriously. We've learned a lot since World War II.([tex]\frac{v_{x}}{c\sqrt{1-\beta^{2}}}[/tex] , [tex]\frac{v_{y}}{c\sqrt{1-\beta^{2}}}[/tex] , [tex]\frac{v_{z}}{c\sqrt{1-\beta^{2}}}[/tex] , [tex]\frac{i}{\sqrt{1-\beta^{2}}}[/tex] )